Question

A force act on a bicycle for 2.4 sec, and changes its momentum from 20 kg m/s in the x positive direction to 40 Kg m/s in the Positive x direction, what is the magnitude of the force?

A. -10 N
B. 137.5 N
C. 8.33 N
D. -137.5 N

Answer 1

Answer: B 137.5
Explanation

Answer 2

Increased momentum =40-20=20

F=P/T=20/2.4=8.33N

Step-by-step explanation:

F=(force)

P=(momentum)

T=(time)