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Solving systems of linear equations algbraically. ​

Solving systems of linear equations algbraically. ​-example-1
User Lada
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1 Answer

1 vote

Answer:

(3,-6)

Explanation:

[1] x - 2y = 15

[2] 2x + 4y = -18

Graphic Representation of the Equations :

-2y + x = 15 4y + 2x = -18

Solve by Substitution :

// Solve equation [1] for the variable x

[1] x = 2y + 15

// Plug this in for variable x in equation [2]

[2] 2•(2y+15) + 4y = -18

[2] 8y = -48

// Solve equation [2] for the variable y

[2] 8y = - 48

[2] y = - 6

// By now we know this much :

x = 2y+15

y = -6

// Use the y value to solve for x

x = 2(-6)+15 = 3

Solution :

{x,y} = {3,-6}

User Matt McClellan
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