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Determine the mass of 2.86 mole Co(NH3)6Cl3

User Leze
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1 Answer

7 votes

Answer:

765 g Co(NH₃)₆Cl₃

General Formulas and Concepts:

  • Reading the Periodic Table of Elements

Step-by-step explanation:

Step 1: Define

2.86 mol Co(NH₃)₆Cl₃

Step 2: Define conversions

Molar Mass of Co - 58.93 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Co(NH₃)₆Cl₃ - 58.93 + 6(14.01) + 18(1.01) + 3(35.45) = 267.52 g/mol

Step 3: Dimensional Analysis


2.86 \ mol \ Co(NH_3)_6Cl_3((267.52 \ g \ Co(NH_3)_6Cl_3)/(1 \ mol \ Co(NH_3)_6Cl_3) ) = 765.107 g Co(NH₃)₆Cl₃

  • mol Co(NH₃)₆Cl₃ and mol Co(NH₃)₆Cl₃ cancel out
  • We are left with grams (mass)

Step 4: Simplify

We are given 3 sig figs. Follow sig fig rules.

765.107 g Co(NH₃)₆Cl₃ ≈ 765 g Co(NH₃)₆Cl₃

User Aaron Gage
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