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31 votes
31 votes
A line has a slope of -3 and passes through the point

passes through the point (-2, -3/2)
By substituting into the equation y = mx + b, find the value of b for this line

User DuneCat
by
3.3k points

2 Answers

11 votes
11 votes

Answer:

If I am not mistaking it should be -7.5

Explanation:

User MacInnis
by
2.4k points
10 votes
10 votes

Answer:

b = -15/2

y = -3x -15/2

Explanation:

The value of the y-intercept can be found from a point and the slope of the line by solving the slope-intercept equation for the intercept.

__

intercept

y = mx + b . . . . . . . equation of a line with slope m and y-intercept b

y -mx = b . . . . . . . . subtract mx from both sides

For the point (x, y) = (-2, -3/2) and slope m = -3, the value of b is ...

b = -3/2 -(-3)(-2) = -3/2 -6

b = -15/2 . . . . . the value of b for this line

__

equation of the line

Then the equation for the line is ...

y = mx +b

y = -3x -15/2

User Sergio Bost
by
2.7k points
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