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A source charge of 3 µc generates an electric field of 2.86 × 105 n/c at the location of a test charge. what is the distance, to the nearest hundredth, of the test charge from the source charge?

User Glutz
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2 Answers

10 votes
10 votes

Answer:

0.307

Step-by-step explanation:

edge22

User Lugaru
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2.8k points
20 votes
20 votes

Hi there!

Recall the equation for the electric field produced by a point charge:


E = (kQ)/(r^2)

E = Electric field (2.86 × 10⁵ N/C)
k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)

Q = Charge (3 × 10⁻⁶ C)
r = distance from center of charge (? m)

Rearrange the equation to solve for 'r'.


r^2 = (kQ)/(E)\\\\r = \sqrt(kQ)/(E)}}\\\\r = \sqrt{((8.99*10^9)(3*10^6))/((2.86* 10^5))} = \boxed{0.307 m}

User Firzen
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3.1k points