Given:
Reservation fee = $19
Additional fee = $6 per hour
The chemistry club wants to spend at most $19 on renting the room.
To find:
The possible numbers of hours the chemistry club could rent the meeting room.
Solution:
Let n be the number of hours the chemistry club could rent the meeting room.
Reservation fee = $19
Additional fee for one hour = $6
Additional fee for n hours = $6n
Total fee = $(6n+19).
The chemistry club wants to spend at most $19 on renting the room. It means the total fee must be less than or equal to 19.
![6n+19\leq 19](https://img.qammunity.org/2021/formulas/mathematics/high-school/t1ndgt8h7nouss0so7mez7qkctxc8dcri8.png)
Subtract 19 from both sides.
![6n\leq 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/mxq65m482vjt6p2tp4yngism8xglzytdad.png)
Divide both sides by 6.
![n\leq 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/ebko8yrz3m2abprpd6e7huqh10vctnuoid.png)
Time can not be negative. So n=0.
Therefore, the possible numbers of hours the chemistry club could rent the meeting room is 0.