Question

Shelby the Skater's rocket provides a forward force of

220 Newtons. Shelby has a mass of 60. kg. If friction
provides a resistive force of 30. Newtons, then at what
rate does Shelby accelerate? Show all work.

Answer 1

`a=3.17\ m/s^2`

Step-by-step explanation:

Given that,

Force force acting on the Skater's rocket is 220 N

Resistive force acting on it, F' = 30 N

Mass of Shelby, m = 60 kg

We need to find the acceleration of Shelby. Net force acting on Shelby is given by :

Net force = 220-30

= 190 N

The formula of net force is :

F = ma

a is acceleration of Shelby

`a=(F)/(m)\\\\a=(190)/(60)\\\\a=3.17\ m/s^2`

So, the acceleration of Shelby is
`3.17\ m/s^2`