Question

Using the quadratic formula to solve x2 = 5-x, what are the values of x?

Answer 1

A) (-1 ± √21)/ 2

Explanation:

Move all terms onto one side

`x^(2)` = 5-x

`x^(2)` + x - 5 = 0

Insert values into quadratic formula

a = 1 b= 1 c= - 5

[-b ± √(
`b^(2)` - 4ac)]/2a

[-1 ± √(
`1^(2)` - 4 (1(-5)]/ 2(1)

(-1 ± √21)/ 2

Answer 2

its the first choice, negative 1 plus or minus square root of 21 over 2

Explanation: