Question

`\sf\large\green{\underbrace{\red{Question*}}}:`


`\mathbb\blue{SOLVE}`

`\pink{1. \: \: \: \: \: \: (3 - x)(x + 2) = 0}`

`\pink{2. \: \: \: \: \: {(q + 2)}^(2) - 40}`
​

Answer 1

`\large{\underline{\underline{\pmb{\sf{\color {red}{Solve:}}}}}}`

`\sf \red{1. \: (3x - x) (x + 2) = 0}`

`\sf \red{2. \: (q + 2)^(2) - 40}`

`\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}`

2.soln:

(q + 2)² - 40

=> (q)² + 2.q.2 + (2)² - 40

=> q² + 4q + 4 - 40

=>q² + 4q - 36

Here, a = 1, b = 4 and c = - 36

By, using Quadratic formula

See the attachment