Question

The handbook density of gold is 19.3

g/cm3. In the lab a student observes it to 18.4 g/cm3. What is her percent error?

Answer 1

Percent error = -4.7%

Step-by-step explanation:

Given data:

Actual density value = 19.3 g/cm³

Measured value of density by student = 18.4 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = ( measured value - actual value / actual value ) × 100

Now we will put the values.

Percent error = ( 18.4 g/cm³ - 19.3 g/cm³ / 19.3 g/cm³) × 100

Percent error = (-0.9 g/cm³ / 19.3 g/cm³) × 100

Percent error = -0.047 × 100

Percent error = -4.7%

Negative sign shows that measured value is less than actual value.