Question

what amount of work done by the system when 24.0 L of H2 expands to new volume of 48.0 L against a constant pressure of 75 atm at 45.3c

Answer 1

1820.4kJ

Step-by-step explanation:

The work of a sample of gas when it expanded under constant pressure follows the formula:

W = P*ΔV

Where P is pressure,

And ΔV is Final Volume - Initial Volume

Replacing:

W = P*ΔV

W = 75atm*(48.0L - 24.0L)

W = 1800atmL

In joules (1atmL = 101.325J):

1800atmL * (101.325J / 1atmL) = 182385J =

1820.4kJ