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Find the number of the natural numbers between 101 and 999 which are divisible by both 2 and 5 in AP



User Tronman
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1 Answer

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110,120,130,...,990


n = (990 - 110)/(10) + 1 \\


n = (880)/(10) + 1 \\


n = 88 + 1


n = 89

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User Fuggly
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