69.0k views
1 vote
On a certain hot​ summer's day, 552 people used the public swimming pool. The daily prices are $1.75 for children and $2.50 for adults. The receipts for admission totaled How many children and how many adults swam at the public pool that​ day?

1 Answer

5 votes

Final answer:

To solve the problem of determining the number of children and adults who swam at the public pool, we can use a system of equations. However, there seems to be a error in the given information, making it impossible to find the solution.

Step-by-step explanation:

To solve this problem, we can use a system of equations. Let's assume that the number of children who swam at the pool is 'C' and the number of adults is 'A'. From the given information, we can set up two equations: C + A = 552 (equation 1) and 1.75C + 2.50A = 56.75 (equation 2).

Now, we can solve this system of equations. Subtracting equation 1 from equation 2, we get (1.75C + 2.50A) - (C + A) = 56.75 - 552, which simplifies to 1.75C + 2.50A - C - A = -495.25.

Combining like terms, we have 0.75C + 1.50A = -495.25. Multiplying both sides of this equation by 4, we get 3C + 6A = -1981. Subtracting equation 1 multiplied by 3 from this equation, we get (3C + 6A) - (3C + 3A) = -1981 - 1656, which simplifies to 3A = -363.

Dividing both sides of this equation by 3, we find A = -121. Since we can't have a negative number of adults, we know there must be an error in the given information. Please double-check the totals provided for the receipt amounts. Without accurate information, we cannot determine the number of children and adults who swam at the pool that day.

User Rafael Merlin
by
5.3k points