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*PLEASE HELP*

An airplane flying parallel to the ground undergoes two consecutive dis-
placements. The first is 75 km 30.0° west of north, and the second is
155 km 60.0° east of north. What is the total displacement of the
airplane?

User Tien Lin
by
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1 Answer

3 votes

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Answer:

172.19 km, N 34.18° E

Step-by-step explanation:

The turn made at the end of the first leg is 90°, so the total displacement can be found using the Pythagorean theorem.

d = √(75^2 +155^2) = √29650

d ≈ 172.19 . . . km

The direction can be found from the angle between the initial leg and the end point. That angle is ...

α = arctan(155/75) ≈ 64.18°

Then the direction from the starting position to the final position is ...

-30° +64.18° = 34.18° . . . . east of north

The total displacement of the airplane is ...

172.19 km, N 34.18° E

*PLEASE HELP* An airplane flying parallel to the ground undergoes two consecutive-example-1
User Jerzy Zawadzki
by
4.4k points