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In this triangle, the product of sin B and tan C is
, and the product of sin C and tan B is
.

2 Answers

3 votes

Answer:

The product of sin B and tan C is (c/a)

The product of sin C and tan B is (b/a)

PLATO

User Jocheved
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The product of sin B and tan C is c/a

The product of sin C and tan B is b/a

Further explanation

We can use

SOH stands for Sine = Opposite ÷ Hypotenuse.

CAH stands for Cosine = Adjacent ÷ Hypotenuse.

TOA stands for Tangent = Opposite ÷ Adjacent.

There is a picture attached


\tt sin~B=(b)/(a)\\\\Tan~C=(c)/(b)\\\\sin~B* Tan~C=(b)/(a)* (c)/(b)=(c)/(a)


\tt sin~C=(c)/(a)\\\\Tan~B=(b)/(c)\\\\sin~C* tan~B=(c)/(a)* (b)/(c)=(b)/(a)

Type the correct answer in each box. If necessary, use / for the fraction bar(s). In-example-1
User Phuong LeCong
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