Type the correct answer in each box. If necessary, use / for the fraction bar(s). In this triangle, the product of sin B and tan C is , and the product of sin C and tan B is .

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asked Mar 10, 2021 100k views

2 Answers

Phuong LeCong · Answer 1 · 2021-03-14T19:42:03+0000

The product of sin B and tan C is c/a

The product of sin C and tan B is b/a

We can use

SOH stands for Sine = Opposite ÷ Hypotenuse.

CAH stands for Cosine = Adjacent ÷ Hypotenuse.

TOA stands for Tangent = Opposite ÷ Adjacent.

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$\tt sin~B=(b)/(a)\\\\Tan~C=(c)/(b)\\\\sin~B* Tan~C=(b)/(a)* (c)/(b)=(c)/(a)$

$\tt sin~C=(c)/(a)\\\\Tan~B=(b)/(c)\\\\sin~C* tan~B=(c)/(a)* (b)/(c)=(b)/(a)$

$Type the correct answer in each box. If necessary, use / for the fraction bar(s). In-example-1$