Answer:
Follows are the solution to this question:
Explanation:
please find the complete question in the attached file.
female = 23 and male = 19 faculty members
Randomly selected member are = 6
In point 1:
The Probability to equally selecting men and women:
In point 2:
The Probability of selecting at least 4 men:
![= (((19C4 * 23C2)+(19C5 * 23C1)+(19C6)))/(42C6)](https://img.qammunity.org/2021/formulas/mathematics/college/etm9v3bzbf32k41xbw5muxpxvupksy88k5.png)
In point 3:
The probability in which no women are chosen implies that 6 selected members are from 23 women:
![= (23C6 )/(42C6)](https://img.qammunity.org/2021/formulas/mathematics/college/lge4plx2nyj34269nka0zclz9is5sp86eu.png)
In point 4:
The Probability in which no more than 4 women are selected:
![(((19C6)+(23C1 * 19C5)+(23C2 * 19C4)+(23C3 * 19C3)+(23C4 * 19C2)))/(42C6)](https://img.qammunity.org/2021/formulas/mathematics/college/z3dskmze81p9wct1he8ts3snqzvbxasntv.png)