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7 votes
Multiply.


(√(2))/(6)cis ((3\pi )/(5))·
(√(6))/(4)cis ((2\pi )/(3))

A.
(√(3))/(12)cis((19\pi )/(15))
B.
(√(3))/(12)cis((2\pi )/(5))
C.
(√(2))/(8)cis((2\pi )/(5))
D.
(√(2))/(8)cis((19\pi )/(15))

User PriNcee
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4.7k points

1 Answer

9 votes

Multiply the moduli and add the arguments:

√2/6 cis(3π/5) × √6/4 cis(2π/3)

= (√2/6 × √6/4) cis(3π/5 + 2π/3)

= √3/12 cis(19π/15) … [A]

User Yota
by
5.0k points