293,455 views
25 votes
25 votes
The nth term of a sequence is represented by
( 2n^3+25n^2+32n-15)/(6n^4+2n^3-11n^2-2n+17)

What is the limit of the nth term as x becomes increasingly large?

A. 0
B. 1/3
C. 3
D. Limit does not exist.

User Nicolas Yuste
by
2.7k points

2 Answers

11 votes
11 votes
I think that the possible answer is 3
User Ppajer
by
3.1k points
22 votes
22 votes

Answer:

A) 0

Step-by-step explanation:


\sf \lim _(x\to \infty )\left((2n^3+25n^2+32n-15)/(6n^4+2n^3-11n^2-2n+17)\right)

1) Limit does not exist when the numerator is bigger.

2) Limit is zero when the denominator is bigger.

3) Limit is the ratio of coefficients when both powers are equal.

Here, the denominator have a power of 4, bigger than the numerator.

Hence, the limit of the nth term is 0.

User Jayesh
by
2.9k points