Question

What is an equation of the line that passes through the points (3, 1)(3,1) and (6, 6)(6,6)? Put your answer in fully reduced form.

Answer 1

9514 1404 393

Answer:

y = (5/3)x -4

Explanation:

The 2-point form of the equation of a line can be written as ...

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (6-1)/(6-3)(x -3)+1 . . . . fill in given point values

y = 5/3(x -3) +1 . . . . . . . . simplify

y = 5/3x -5 +1 . . . . . . . . . .eliminate parentheses

y = 5/3x -4 . . . slope-intercept form of equation