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Integrate 1/x(x-1) dx

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Decompose the integrand into partial fractions:

1 / (x (x - 1)) = 1/(x - 1) - 1/x

Then

∫ 1 / (x (x - 1)) dx = ln|x - 1| - ln|x| + C = ln|1 - 1/x| + C

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