Question

How much voltage is present in a circuit that carries 0.02 A with a resistance of 400 Ω?

Answer 1

8V

Step-by-step explanation:

Given parameters:

Current = 0.02A

Resistance = 400Ω

Unknown:

Voltage in the circuit = ?

Solution:

The voltage in a circuit is the driving force of the system.

According to ohms law;

V = IR

V is the voltage

I is the current

R is the resistance

So;

input the parameters and solve;

V = 0.02 x 400 = 8V