Question

The 300 students at Holmes School work a total of 5000 hours each month. Each

student in group A works 10 hours, each in group B works 15 hours, and each in

group C works 20 hours each month. There are twice as many students in group B as

in group A. Which equation would not be included in the system used to solve this

problem?

AB=2A

CA + B + C = 300

B 10A + 15B + 200 = 5000 D A = 2B

Answer 1

`A = 2B`

Explanation:

Given

`Students = 300`

`Hours = 5000`

`Group\ A = 10`

`Group\ B = 15`

`Group\ C = 20`

Required

Which of the options is incorrect?

From the question, we understand that there are 300 students.

This implies that:

`A + B + C = 300`

From the question, we understand that there are 5000 hours.

This implies that:

`10A + 15B + 20C = 5000`

Also, we understand that there are twice as many B as A.

This implies that:

`B = 2A`

So, from the list of given options and the analyses done above.

`A = 2B`

is the odd one among them