Question

HELP calculate the morality of a solution prepared by the addition of 2.59g of nano3 into 250 ml of solution

Answer 1

M = 0.12 M

Step-by-step explanation:

Given data:

Mass of NaNO₃ = 2.59 g

Volume of solution = 250 mL

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 2.59 g/ 85 g/mol

Number of moles = 0.03 mol

Volume in Litters:

250 mL × 1 L/1000 mL

0.25 L

Molarity:

M = 0.03 mol/0.25 L

M = 0.12 mol/L