Question

#6.

A bird, accelerating from rest at a constant rate, experiences a displacement of 28 m in lls,
What is the final velocity after 11 s?

Answer 1

Vf = 5.09 [m/s]

Step-by-step explanation:

To solve this problem we must use the equations of kinematics. Where we must first find the acceleration, then find the final velocity.

`x-x_(o) =(v_(o)*t) +(1)/(2)*a*t^(2) \\`

where:

X - Xo = 28 [m]

Vo = initial velocity = 0 (starting from the rest)

t = time = 11 [s]

28 = 0.5*a*(11)²

a = 0.462 [m/s²]

Now the final velocity can be calculated by means of the following equation.

`v_(f) ^(2) = v_(o) ^(2) + 2*a*x\\`

where:

Vf = final velocity [m/s]

Vf² = (2*0.462*28) (using the rootsquared)

Vf = 5.09 [m/s]