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9f+5(−8f+1)≤3f+7-10f+3f+7−10f

User Zon
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2 Answers

2 votes

Answer:


\boxed{f \leqslant (1)/(5) }

Explanation:


9f+5(−8f+1)≤3f+7-10f+3f+7−10f \to \\ \\ 31f + 5 \leqslant - 14f + 14 \\ \\ 45f \leqslant 9 \\ f \leqslant (9)/(45) \\ \boxed{f \leqslant (1)/(5) }

♨Rage♨

User Diewland
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F>-9/17. !!!!!!! I’m serious
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User Rantiev
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