Question

Steve Cram of Great Britain ran a mile in 3.81 min. During this amazing run, what was Steve's average velocity in mi/hr

Answer 1

v = 15.72 mi/hr

Step-by-step explanation:

It is given that,

Steve Cram of Great Britain ran a mile in 3.81 min

We need to find Steve's average velocity in mi/hr.

Speed,

`v=(d)/(t)\\\\v=\frac{1\ \text{mile}}{3.81\ \text{}min}\\\\v=0.262\ mi/min`

We know that,

1 hour = 60 minute

So, average speed is :

`v=\frac{0.262\ \text{mile}}{\text{min}}\\\\v=\frac{0.262\ \text{miles}}{(1)/(60)h}\\\\v=15.72\ mi/hr`

So, the average velocity is 15.72 mi/h.