Question

A ballon has a volume of 5.6L at 25C and it is placed into liquid nitrogen at a temp of -78c. what is the volume of the ballon

Answer 1

3.7L

Step-by-step explanation:

Given parameters:

Initial volume = 5.6L

Initial temperature = 25°C = 273 + 25 = 298K

Final temperature = -78°C = 273 + (-78) = 195K

Unknown:

New volume of the balloon = ?

Solution:

We are going to assume that the pressure is constant and then we apply the charles's law;

"the volume of fixed mass of a gas varies directly as its absolute temperature if its pressure is constant"

mathematically;

`(V_(1) )/(T_(1) )` =
`(V_(2) )/(T_(2) )`

Where V and T are temperature

1 and 2 are initial and final states

Insert the parameters and solve;

`(5.6)/(298)` =
`(V_(2) )/(195)`

298V₂ = 1092

V₂ = 3.7L