Question

Which equation is y = –6x2 + 3x + 2 rewritten in vertex form?

y = negative 6 (x minus 1) squared + 8
y = negative 6 (x + one-fourth) squared + thirteen-eighths
y = negative 6 (x minus one-fourth) squared + nineteen-eighths
y = negative 6 (x minus one-half) squared + seven-halves

Answer 1

Explanation:

y = negative 6 (x minus one-fourth) squared + nineteen-eighths

Explanation:

y = –6x^2 + 3x + 2

Divide the first 2 terms of the right side by -6:

y = -6(x^2 - 1/2x) + 2

Now complete the square on the expression in the brackets:

y = -6[(x - 1/4)^2 - 1/16] + 2

y = -6(x - 1/4)^2 + 6/16 + 2

y = -6(x - 1/4)^2 + 38/16

y = -6(x - 1/4)^2 + 19/8