Answer:
There are 1,890 seats in the hall
Explanation:
The number of seats in the first row = 20 seats
The number of rows in the hall = 35 rows
The number of additional seat per row = 2 Seat
Therefore, the sequence of seats in the hall is an arithmetic sequence with the first term, a = 25, the common difference, d = 2, and the number of terms, n = 35
The formula for finding the sum of n-terms of an arithmetic progression, Sₙ is given as follows;
Sₙ = n/2 × [2·a + (n - 1)·d]
Plugging in the values, we get;
Sₙ = 35/2 × [2 × 25 + (35 - 1)×2] = 1890 seats
Therefore, there are 1,890 seats in the hall.