Answer: (0,5)
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Work Shown:
y-5 = x^2
y = x^2 + 5 ... add 5 to both sides
y = 1x^2 + 5
y = 1(x-0)^2 + 5 ... x replaced with (x-0)
The equation is now in the form y = a(x-h)^2 + k
We have a = 1, h = 0, k = 5.
The vertex is (h,k) = (0,5)
The value of 'a' determines how vertically stretched or compressed the parabola is. Also, if a > 0, then the parabola opens upward; or if a < 0, then the parabola opens downward.