Question

In an experiment, two unknown compounds (one an alcohol and the other an amine) of equal molecular mass were heated. The result of the experiment shows that Compound A boiled at a lower temperature than Compound B.

Which of the following correctly explains the identity of Compound A and why this was the result? (4 points)

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.
It is an amine; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.

Answer 1

Answer: It is an amine; it contains nitrogen-hydrogen bonds that are less polar than oxygen-hydrogen bonds.

Explanation: I TOOK THE TEST AND GOT IT RIGHT

Answer 2

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.

Step-by-step explanation:

The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.

Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.

A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.

The order of strength of the bond is;

H.....F > H.....O > H......N

In amines we have the H....N hydrogen bonds, for alcohol, it is the H....O hydrogen bonds.

So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.