Question

1. Magnesium Bromide

Step 1: Write out the charges for each ion (2pts)

Step 2: Do the charges cancel out? (1pts)

Step 3: Determine how many of each ion is needed to make the overall charge zero. (1pts)

Step 4: Write the correct formula, correct order and amount of each ion. (2pts)



2. Zinc Phosphide

Step 1: Write out the charges for each ion (2pts)

Step 2: Do the charges cancel out? (1pts)

Step 3: Determine how many of each ion is needed to make the overall charge zero. (1pts)

Step 4: Write the correct formula, correct order and amount of each ion. (2pts)

Answer 1

The compound formula can be determined from the charge of the constituent elements of the compound

Further explanation

There are several compounds :

ion compounds, covalent compounds, and polyatomic

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

• Magnesium Bromide

1. Mg²⁺, Br⁻

2. no, +2(Mg) + -1(Br)=+2-1=+1

3. Mg²⁺ 1 ion, Br⁻ need 2 ion

4. MgBr₂, 1 Mg and 2 Br

• Zinc Phosphide

1. Zn²⁺, P³⁻

2. no, +2(Zn)+ -3(P)=2-3=-1

3. Zn need 3 ion, P 2 ion

4. Zn₃P₂, 3 Zn and 2 P