Question

Find the equivalent resistance of this circuit.​

Answer 1

`\huge{\boxed{\mathcal{♔︎Answer♔︎}}}`

200Ω

Step-by-step explanation:

⠀

⠀

⠀⠀⠀⠀❖ Note

⠀

What is resistance?

Resistance is the opposition offered by the electric current.

⠀

What is electric current?

An electric current is the stream of flowing charge moving around a circuit.

⠀

⠀

⠀⠀⠀⠀■ Solution

⠀

`\textsf{ As here, we can see in the above diagram} \\ \\ \sf R_1 \: and \: R_2 \: both \: are \: in \: series. \\ \\ \textsf{ So their total resistance will be} \: R_s`

So for formula for series will be

`\sf R_s = R_1 + R_2 \\ \\ \sf R_s = 100 + 200 \\ \\ \boxed {R_s = 300Ω}`

⠀

`\sf As \: you \: can \: also \: see \: here , \\ \\ \sf R_s \: is parallel \: with \: R_3 \\ \\ \sf So \: their \: total \: resistance \: R \: will \: be`

⠀

`\sf (1)/(R ) = (1)/(R_3) + (1)/(R_s ) \\ \\ \sf (1)/(R) = (1)/(600) + (1)/(300) \\ \\ \sf (1)/(R) = (1 + 2)/(600) \\ \\ \sf (1)/(R) = \frac{ \cancel3}{ \cancel{600} \: \: \small{200}} \\ \\ \sf (1)/(R) = (1)/(200) \\ \\ \boxed{ \tt{R = 200Ω}}`

⠀

⠀

So the total resistance will be 200Ω.