Question

Find the equivalent resistance of this circuit. First, what is the equivalent resistance, Req(23), of the parallel combination of R2 and R3?​

Answer 1

`R_(eq(23)) = \left(\frac 1{R_2} + (1)/(R_3)\right)^(-1)\\\\\\~~~~~~~~~= \left( \frac 1{200} + \frac 1{300} \right)^(-1)\\\\~~~~~~~~~=\left( (5)/(600) \right)^(-1)\\\\\\~~~~~~~~~=\frac{600}5\\\\\\~~~~~~~~~= 120~ \Omega`

Answer 2

Step-by-step explanation :

Here we have to calculate the equivalent resistance of the parallel combination between R2 and R3.

As we know that,

• 1/Rp = 1/R2 + 1/R3 ... n

>> 1/Rp = (1/200) + (1/300)

>> 1/Rp = (300 + 200 / 600)

>> 1/Rp = 500 / 600

>> 1/Rp = 5 / 6

>> Rp = 6 / 5

>> Rp = 1.2Ω

Therefore,

• Resistance in parallel combination is of 1.2Ω