Question

There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun

one time, what is the probability that the result is a multiple of 4 or a multiple of 3?

Answer 1

`the \: probability \: that \: the \: result \: is \: a \\ \: multiple \: of \: 4 \: or \: a \: multiple \: of \: 3 \: is \: \to \\ \boxed{ (7)/(13) }`

Explanation:

`let \: the \: proberbility \: be : \rho \\ then \: the \: proberbility \: ( \rho) \: is \: given \: as : \\ \rho = (number \: of \: possible \: outcome)/(total \: number \: of \: possible \: outcome) \\ where \\ number \: of \: possible \: outcome = 3 + 4 = 7 \\ total \: number \: of \: possible \: outcome = 13 \\ hence : \to \\ \boxed{\rho = (7)/(13) }`

♨Rage♨

Answer 2

6/13

Explanation:

There are 13 numbers between 1 and 13. There are 6 numbers that are multiples of 4 or 3: 3, 4, 6, 8, 9, and 12.

So the probability is 6/13.