Question

What is the molarity of a sodium chloride solution that has 2.3 moles of NaCl in a volume of 350 mL?

Answer 1

`6.5714\text{M}`

Step-by-step explanation:

Number of moles of NaCl = 2.3 moles

Volume = 350 mL =
`350* 10^(-3)\ \text{L}=0.35\ \text{L}`

Molarity is given by

`M=\frac{\text{Number of moles of NaCl}}{\text{Volume}}`

`\Rightarrow M=(2.3)/(0.35)`

`\Rightarrow M=6.5714\text{M}`

Molarity of the solution is
`6.5714\text{M}`