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A charge of +0.4 C is moved from a position where the electric potential is 20 V to a position where the electric potential is 50 V. What is the change in potential energy of the charge associated with the change in position

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User Gopalkrizna
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Change in potential energy = work done = Q x ΔV = 0.4 x 30 = 12 Joules
User Pedromss
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