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Find the standard​ deviation, ​, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n​503; p0.7

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Answer: 10.28

Explanation:

For the binomial distribution ,

standard deviation :
\sigma=√(p(1-p)n), where p = population proportion, n = sample size.

Given: n= 503 and p=0.7

Then,
\sigma=√(503*0.7(1-0.7))=√(105.63)\approx10.28

Hence, the standard​ deviation = 10.28

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