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The temperature of liquid in an experiment starts at 0*C. The experiment calls for the temperature of the liquid to change at a rate of -0.60*C per minute. How long will it take for the liquid to reach -10.5*C

User Embarus
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1 Answer

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Answer:

The liquid will take 17.5 minutes to reach -10.5 ºC.

Explanation:

From this statement we understand that the temperature of liquid is increased at constant rate in time, whose model is described by:


T (t) = \dot r \cdot t + T_(o) (Eq. 1)

Where:


T - Temperature of the liquid, measured in degrees Celsius.


\dot r - Heating rate, measured in degrees Celsius per minute.


t - Time, measured in minutes.


T_(o) - Initial temperature, measured in degrees Celsius.

If we know that
\dot r = -0.60\,(^(\circ)C)/(min) and
T_(o) = 0\,^(\circ)C, the temperature model for the liquid is:


T(t) = -0.60\cdot t (Eq. 2)

In addition, if
T(t) = -10.5\,^(\circ)C, then time taken for the liquid to reach that temperature is:


t = (-10.5)/(-0.60)


t = 17.5\,min

The liquid will take 17.5 minutes to reach -10.5 ºC.

User Tdracz
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