Question

Veronica is ordering trophies for her school. Company P charges $3.50 for each trophy and a one-time engraving fee of $25. Company R charges $7.50 for each trophy and a one-time engraving fee of $17. Which inequality can be used to find x, the minimum number of trophies that can be ordered so that the total charge at Company P is less than the total charge at Company R?

Answer 1

<2

Explanation:

Answer 2

Answer: Required inequality :
`3.50x+25<7.50x+17`

Solution: x<2.

Explanation:

Let x = number of trophies.

Company P charges $3.50 for each trophy and a one-time engraving fee of $25.

Total charge for x trophies from Company P=
`3.50x+25`

Company R charges $7.50 for each trophy and a one-time engraving fee of $17.

Total charge for x trophies from Company R =
`7.50x+17`

When total charge at Company P is less than the total charge at Company R, then

`3.50x+25<7.50x+17\\\\\Rightarrow\ 7.5x-3.5x<25-17\\\\\Rightarrow\ 4x<8\\\\\Rightarrow\ x<2`

Required inequality :
`3.50x+25<7.50x+17`

Solution: x<2.