Question

How many grams of NO2 would be formed from 1.0 mole of NO and excess of O2?

Answer 1

Mass = 46 g

Step-by-step explanation:

Given data:

Number of moles of NO = 1.0 mol

Amount of O₂ = excess

Mass of NO₂ formed = ?

Solution:

Chemical equation:

2NO + O₂ → 2NO₂

Now we will compare the moles of No with NO₂.

NO : NO₂

2 : 2

1 : 1

Mass of NO₂ in gram:

Mass = number of moles × molar mass

Mass = 1 mol ×46 g/mol

Mass = 46 g