Question

Use an addition or subtraction formula to find the exact value of sin(19π/12)=−\sqrt{A}(\sqrt{B}+1)/4.

A,B=?

Answer 1

`B = {((4A * sin( (19π)/(12)))/(√(A)))}^(2) + 1`

Explanation:

`sin(19π/12)=−√(A)(√(B)+1)/4A \to \\ \\ sin( (19π)/(12))=− (√(A)(√(B)+1))/(4A)</p><p> \\ \\ √(A)(√(B)+1) = 4A * sin( (19π)/(12)) \\ \\ (√(B)+1) = (4A * sin( (19π)/(12)))/(√(A)) \\ \\ B = {((4A * sin( (19π)/(12)))/(√(A)))}^(2) + 1`

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