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Does anybody understand this? QSRT is a Rectangle and SQR=55

Does anybody understand this? QSRT is a Rectangle and SQR=55-example-1
User Jenniva
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1 Answer

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14 votes

Answer:

90°; 55°; 35°; 110°; 70°

Explanation:

A rectangle has corner angles that are 90°. When the corner angle is divided into two parts, the total of the parts is 90°.

Each of the triangles is isosceles. The figure is symmetrical about its center.

An exterior angle to a triangle is equal to the sum of the remote interior angles.

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∠SRT = 90° . . . . a corner angle

∠STR = 55° . . . . symmetrical to the given angle

∠QRS = 180° -55° -90° = 35° . . . . sum of angles in ΔQRS is 180°

∠QPT = 2×55° = 110° . . . . exterior angle to ΔQPS; ∠QSP =∠SQP

∠TPR = 180° -110° = 70° . . . . forms a linear pair with ∠QPT

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There are numerous ways to figure any or all of these angles. They come down to the fundamentals: angles in a triangle total 180°; angles that form a line total 180°; corner angles of a rectangle are 90°. Base angles of an isosceles triangle are congruent.

The exterior angle rule derives from the sum of angles in a triangle and on a line both being 180°.

User Ameerah
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