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A wagon, initially traveling at a constant 8.5 m/s, starts going down a hill that creates an

acceleration of 4.1 m/s2. How far downhill has the wagon gone after 2.7 s ?

User Boriqua
by
7.6k points

1 Answer

2 votes

Answer:

Step-by-step explanation:

Given parameters:

Initial velocity = 8.5m/s

Acceleration = 4.1m/s²

Time = 2.7s

Unknown:

Distance downhill traveled = ?

Solution:

To solve this problem, we have to adopt the right motion equation;

S = ut +
(1)/(2)at²

where s = distance

u = initial velocity

a = acceleration

t = time taken

Insert the parameters and solve;

S = (8.5 x 2.7) + (
(1)/(2) x 4.1 x 2.7²)

S = 22.95 + 14.95

S = 37.9m

User Swaff
by
7.9k points