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5 votes
Find the differential of the function

a. y=x4sin(9x)
b. y=x4sin⁡(9x).

User Stroboskop
by
7.2k points

1 Answer

3 votes

Answer:

We want to find:


y'*dx = dy

Where:


y = x^4*sin(9x)

Remember that when we have a function like:

f(x) = g(x)*h(x)

The derivation gives:

f'(x) = g'(x)*h(x) + g(x)*h'(x)

In this case we can define:

f(x) = y

g(x) = x^4

h(x) = sin(9x)

These functions are easy to differentiate:

g'(x) = 4*x^3

h'(x) = 9*cos(9*x)

Then we have:


y' = (dy)/(dx) = 4x^3*sin(9x) + x^4*9cos(9x)

Then we can write:


dy = (4x^3*sin(9x) + 9x^4*cos(9x))dx

User Ymajoros
by
6.8k points
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