Question

A 33 ​% dextrous solution ​( 33 mg per 100 mL of​ solution) is given intravenously. Suppose a total of 1.936 L of the solution is given over a n 11-hour period. Complete parts​ (a) through​ (c) below.

what is the flow rate in units of ml/hr?

​mL/hr ​(Type an integer or decimal rounded to the nearest thousandth as​ needed.)

What is the flow rate in per​ hour?

nothing ​mg/hr ​(Type an integer or decimal rounded to the nearest thousandth as​ needed.)

b. If each mL contains 16 drops​ (the drop factor is expressed as 16 ​gtt/mL), what is the flow rate in units of​ gtt/hr?

nothing ​gtt/hr ​(Type an integer or decimal rounded to the nearest thousandth as​ needed.)

c. During the 11 ​-hour ​period, how much is​ delivered?

nothing mg ​(Type an integer or decimal rounded to the nearest thousandth as​ needed.)

Answer 1

`176\ \text{ml/hr}`

`58.08\ \text{mL/hr}`

`11\ \text{gtt/hr}`

`638.88\ \text{mg}`

Explanation:

33 ​% dextrous solution ​( 33 mg per 100 mL of​ solution)

1.936 L of the solution is given over an 11-hour period

So the flow rate in mL/hr is

`(1.936* 10^3)/(11)=176\ \text{ml/hr}`

The flow rate in ml/hr is
`176\ \text{ml/hr}`

Flow rate of dextrous in mL/hr is

`0.33* 176=58.08\ \text{mL/hr}`

The flow rate dextrous in mL/hr is
`58.08\ \text{mL/hr}`

Each mL contains 16 drops​ so flow rate in gtt/h is

`(176)/(16)=11\ \text{gtt/hr}`

The flow rate in units of​ gtt/hr is
`11\ \text{gtt/hr}`

The mass of dextrous delivered 11 hours in mg is

`0.33* 1.936* 10^3=638.88\ \text{mg}`

The mass of dextrous delivered 11 hours in mg is
`638.88\ \text{mg}`