183k views
4 votes
A 10 foot ladder leans against a building that is 8 feet off of the ground. At what height would a 25 foot ladder touch the building if both ladders form the same angle with the ground?

1 Answer

3 votes

Answer:

19.99feet

Explanation:

The set up will form a right angles triangle:

First we need to get the angle of elevation of the first ladder using SOH, CAH, TOA

The length of the ladder will be the hypotenuse = 10foot

The opposite will be the height of the building = 8ft

Using Sin(theta) = opposite/hyp

sin Theta = 8/10

theta = sin^{-1}0.8

theta = 53.13°

If the length of the ladder is now 25 foot, the height of the building will be calculated as shown;

sin Theta = h/25

sin53.13 = h/25

h = 25sin53.13

h = 19.99feet

Hence the height of the building will be 19.99feet

User Anserk
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.