Answer:
![B=3.29\ \mu T](https://img.qammunity.org/2021/formulas/physics/college/p1v02av841h42ma2b4kqybn2rkyakfjpu3.png)
Step-by-step explanation:
Given that,
Length of a wire is 3 m
Current in the wore, I = 10 A
The wire formed a semicircle.
We need to find the magnitude of the magnetic field (in micro-tesla) at the center of the circle along which the wire is placed.
The magnetic field at the center of semicircle is given by :
![B=(\mu_o I)/(4R)](https://img.qammunity.org/2021/formulas/physics/college/os1e7xbuz99jd9f5df8lacj1yugpgw8fls.png)
R is radius of semicircle,
![R=(3)/(\pi)=0.954\ m](https://img.qammunity.org/2021/formulas/physics/college/cnwpzs73pg47pd3tc673bpkks78lcmaysn.png)
So,
![B=(4\pi * 10^(-7)* 10I)/(4(0.954))\\\\B=3.29* 10^(-6)\ T\\\\B=3.29\ \mu T](https://img.qammunity.org/2021/formulas/physics/college/att7ucbf7budcy8yfaqp8e81ztnjvbp7ok.png)
So, the magnitude of the magnetic field is
.