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A segment of wire of total length 3 m carries a 10 A current and is formed into a semicircle. Determine the magnitude of the magnetic field (in micro-tesla) at the center of the circle along which the wire is placed.

User Nitimalh
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1 Answer

7 votes

Answer:


B=3.29\ \mu T

Step-by-step explanation:

Given that,

Length of a wire is 3 m

Current in the wore, I = 10 A

The wire formed a semicircle.

We need to find the magnitude of the magnetic field (in micro-tesla) at the center of the circle along which the wire is placed.

The magnetic field at the center of semicircle is given by :


B=(\mu_o I)/(4R)

R is radius of semicircle,


R=(3)/(\pi)=0.954\ m

So,


B=(4\pi * 10^(-7)* 10I)/(4(0.954))\\\\B=3.29* 10^(-6)\ T\\\\B=3.29\ \mu T

So, the magnitude of the magnetic field is
3.29\ \mu T.

User Ram Mandal
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6.1k points