Question

An athlete swings a 6.50-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.900 m at an angular speed of 0.700 rev/s. (a) What is the tangential speed of the ball

Answer 1

v = 3.951 m/s

Step-by-step explanation:

Given that,

Mass of a ball, m = 6.5 kg

Radius of the circle, r = 0.9 m

Angular speed of the ball,
`\omega=0.7\ rev/s=4.39\ rad/s`

Let v is the tangential speed of the ball. It is given in terms of angular speed is follows :

`v=r\omega\\\\v=0.9* 4.39\\\\v=3.951\ m/s`

So, the tangential speed of the ball is 3.951 m/s.