Question

A 1.5 kg rightward moving air glider decreases its speed from 1.872 meters per second to 1.798 meters per second over the length of 1 M long track. Determine the net force acting upon the air glider

Answer 1

The magnitude of the net force is 0.204 N.

Step-by-step explanation:

The net force acting upon the air glider is:

`F = ma`

Where:

m: is the mass of the air glider = 1.5 kg

a: is the acceleration

First, we need to find the acceleration. Since we have the initial and final speed we can calculate the acceleration as follows:

`v_(f)^(2) = v_(0)^(2) + 2ad`

Where:

`v_(f)`: is the final speed = 1.798 m/s

`v_(0)`: is the initial speed = 1.872 m/s

d: is the distance = 1 m

The acceleration is:

`a = (v_(f)^(2) - v_(0)^(2))/(2d) = ((1.798 m/s)^(2) - (1.872)^(2))/(2d) = -0.136 m/s^(2)`

The minus sing is because the air glider is desaccelerating.

Now, the magnitude of the net force is:

`|F| = ma = 1.5 kg*0.136 m/s^(2) = 0.204 N`

Therefore, the magnitude of the net force is 0.204 N.

I hope it helps you!